Question

Диме и маме вместе 40 лет, Диме и папе вместе 42 года, маме и папе вместе 74 года. Сколько лет каждому?

Answer 1

Диме и маме вместе 40 лет, Диме и папе вместе 42 года, значит папа старше мамы на 2 года. Пусть х лет маме, тогда х+2 лет папе, маме и папе вместе 74 года, значит х+х+2=74

                          2х=72

                             х=6

36 лет маме, тогда 38 лет папе.

 

у лет Диме, Диме и маме вместе 40 лет, значит

у+36=40

у=4

Диме 4 года

 

 

Answer 2

Solution:

To solve this problem, we can use a system of linear equations to find the ages of Dima, his mother, and his father.

Let's denote: - Dima's age as D - Dima's mother's age as M - Dima's father's age as F

We have the following information: 1. D + M = 40 (Dima and his mother together are 40 years old) 2. D + F = 42 (Dima and his father together are 42 years old) 3. M + F = 74 (Dima's mother and father together are 74 years old)

We can solve these equations to find the ages of each person.

Calculation:

Adding equations (1) and (2) gives: 2D + M + F = 82 (Equation 4)

Adding equations (1) and (3) gives: D + M + F = 114 (Equation 5)

Subtracting equation (4) from equation (5) gives: D = 32

Substituting D = 32 into equation (1) gives: 32 + M = 40 M = 8

Substituting D = 32 into equation (2) gives: 32 + F = 42 F = 10

Answer:

So, the ages are: - Dima is 32 years old - Dima's mother is 8 years old - Dima's father is 10 years old