Question

Один трактор работал в неделю 50 ч,другой 48ч.Оба трактора при одинаковой норме израсходовали за неделю 686 л горючего.Сколько литров горючего израсходовал за неделю каждый трактор?

Answer 1

Один трактор работал в неделю 50 ч,другой 48ч.Оба трактора при одинаковой норме израсходовали за неделю 686 л горючего.Сколько литров горючего израсходовал за неделю каждый трактор?

1) 50+48=98 часов
2) 686:98= 7 литров за 1 час
3) 50*7=350 литров израсх.1 трактор
4) 48*7=336 литров израсх.2 трактор

Answer 2

1) 50 + 48 = 98ч - всего работали оба трактора.
2) 686 : 98 = 7л в час тратит горючего каждый трактор
3) 50 * 7 = 350л израсх. 1-ый
4) 48 * 7 = 336л 2-ой

Answer 3

Calculating Fuel Consumption for Each Tractor

To calculate the fuel consumption for each tractor, we can use the given information. Let's denote the fuel consumption for the first tractor as x liters and for the second tractor as y liters.

We know that the first tractor worked for 50 hours in a week, and the second tractor worked for 48 hours in a week. Both tractors, at the same rate, consumed a total of 686 liters of fuel in a week.

Using this information, we can set up the following system of equations:

1. 50x + 48y = 686 (total fuel consumption for both tractors) 2. x = y (both tractors have the same fuel consumption rate)

Solving the Equations

We can solve the system of equations to find the fuel consumption for each tractor.

Substituting the second equation into the first equation: 50x + 48x = 686 98x = 686 x = 686 / 98 x = 7

Since x = y, the fuel consumption for each tractor is 7 liters.

Answer

Each tractor consumed 7 liters of fuel in a week.