Question

Токарь выоточил y деталей, другой на семь деталей больше, а третий на восемь меньше чем второй. вместе они сделали 81 деталь. Суть задачи в том чтобы решить сколько сделал каждый токарь при помощи уравнений.

Answer 1

1-у деталей 2-(у+7) деталей 3- (у+7-8)=у-1 деталей У+у+7+у-1=81 3у=75 У=25 первый 2- 32 3-24

Answer 2

Problem Analysis

We have three turners who have produced a total of 81 parts. The second turner has produced seven more parts than the first turner, and the third turner has produced eight fewer parts than the second turner. We need to determine how many parts each turner has produced.

Solution

Let's assume that the first turner has produced x parts.

According to the problem, the second turner has produced seven more parts than the first turner. So, the second turner has produced (x + 7) parts.

Similarly, the third turner has produced eight fewer parts than the second turner. So, the third turner has produced ((x + 7) - 8) parts, which simplifies to (x - 1) parts.

The total number of parts produced by all three turners is given as 81. Therefore, we can write the equation:

x + (x + 7) + (x - 1) = 81

Simplifying the equation:

3x + 6 = 81

Subtracting 6 from both sides:

3x = 75

Dividing both sides by 3:

x = 25

So, the first turner has produced 25 parts.

The second turner has produced (25 + 7) = 32 parts.

The third turner has produced ((25 + 7) - 8) = 24 parts.

Therefore, the first turner has produced 25 parts, the second turner has produced 32 parts, and the third turner has produced 24 parts.

Answer

The first turner has produced 25 parts, the second turner has produced 32 parts, and the third turner has produced 24 parts.