Question

(16в кубе:128-5в квадрате) все в кубе -3в кубе

Answer 1

(4096/103)^-3=1/64000 вроде

Answer 2

I can help you with your math problem. Here is the detailed solution:

The given expression is $(\frac{16v^3}{128-5v^2})^3-3v^3$. We can simplify it by following these steps:

- Factor out the common term $v^2$ from the denominator: $(\frac{16v^3}{v^2(25-v)})^3-3v^3$. - Cancel out the common factor $v^2$ from the numerator and denominator: $(\frac{16v}{25-v})^3-3v^3$. - Expand the cube using the binomial formula: $\frac{4096v^3-12288v^2+12288v-4096}{(25-v)^3}-3v^3$. - Subtract $3v^3$ from the numerator: $\frac{4093v^3-12288v^2+12288v-4096}{(25-v)^3}$. - Simplify the fraction by dividing both the numerator and denominator by $v$: $\frac{4093v^2-12288v+12288-4096/v}{(25-v)^2}$.

The final answer is $\frac{4093v^2-12288v+12288-4096/v}{(25-v)^2}$.Ответь+подробно.+(16в+кубе:128-5в+квадрате)+все+в+кубе+-3в+кубе