Question

Для покраски четырёх стен было израсходовано 3 одинаковых бидона краски на первую стену ушло 11 кг краски на вторую -на3 кг больше чем на первую на третью на5 кг больше чем на вторую а на четвёртую на3 кг меньше чем на третью сколько килограммов краски было в каждом бидоне

Answer 1

11кг первая стена
14кг вторая
19кг третья
16кг четвертая
11+14+19+16=60кг всего
60/3=20кг в каждом бидоне

Answer 2

Calculation of Paint in Each Can

To calculate the amount of paint in each can, we need to analyze the given information. Let's break it down step by step:

1. The first wall required 11 kg of paint. 2. The second wall required 3 kg more paint than the first wall. 3. The third wall required 5 kg more paint than the second wall. 4. The fourth wall required 3 kg less paint than the third wall.

Let's assign variables to represent the amount of paint in each can. Let's call the amount of paint in the first can "x" kg.

Based on the given information, we can calculate the amount of paint in each can as follows:

- First can: x kg - Second can: (x + 3) kg - Third can: (x + 3 + 5) kg - Fourth can: (x + 3 + 5 - 3) kg

Now, let's solve for "x" to find the amount of paint in each can.

1. The first wall required 11 kg of paint, so we have the equation: x = 11

2. Substituting the value of "x" in the equations for the second, third, and fourth cans, we get: - Second can: (11 + 3) kg = 14 kg - Third can: (11 + 3 + 5) kg = 19 kg - Fourth can: (11 + 3 + 5 - 3) kg = 16 kg

Therefore, the amount of paint in each can is as follows: - First can: 11 kg - Second can: 14 kg - Third can: 19 kg - Fourth can: 16 kg

Please note that these calculations are based on the given information and assumptions made.