Вопрос задан 27.04.2019 в 16:21. Предмет Математика. Спрашивает Барешева Камила.

На уборке пшеницы в колхозе работали 3 комбайна. Первым убрано 0,36 всей площади, вторым - 3/4

остатка,а третьим - на 8 га меньше, чем вторым. Сколько гектаров убрал каждый комбайн? (х га вся площадь) Три отряда пионеров занимались посадкой деревьев. Первый отряд посадил 36% всех деревьев, второй - 8/9 того, что посадил первый отряд, а третий отряд - все остальные деревья. Сколько деревьев посадил каждый отряд, если первый отряд посадил на 10 деревьев больше третьего? (х деревьев всего) В библиотеке имеются книги на русском, английском и немецком языках. Число книг на англ. языке равно 40% числа всех книг, а число книг на немецком состовляет 1/4 числа книг на англ языке. Сколько в библиотеке книг на русском языке, если их больше на 480 штук, чем на англ? (х книг всего)
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Отвечает Григорьев Дима.
#1
S-x
0,36x+(x-0,36x)0,75+(x-0,36x)0,75-8=x
0,36x+0,48x+0,48x-x=8
0,32x=8|:0,32
x=25(га)-S
1=25*0,36=9(га)
2=(25-9)0,75=12(га)
3=12-8=4га
#2
всего-x
0,36x+0,36x*8/9+0,36x-10=x
0,72x-x+0,32x=10
0,04x=10|:0,04
x=250(д)-всего
1=250*0,36=90д
2=90*8/9=80д
3=90-10=80д
#3
всего-x
0,4x+0,4x*1/4+0,4x+480=x
0,8x+0,1x-x=-480
-0,1x=-480|:(-0,1)
x=4800(кн)-всего
на русском=4800*4/10+480=2400кн
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Problem 1: Уборка пшеницы в колхозе

According to the problem statement, there were 3 combines working in the collective farm (колхоз) to harvest wheat. The first combine harvested 0.36 of the total area, the second combine harvested 3/4 of the remaining area, and the third combine harvested 8 hectares less than the second combine.

To find out how many hectares each combine harvested, let's solve the problem step by step.

Let's assume the total area of the wheat field is x hectares.

1. The first combine harvested 0.36 of the total area, which is 0.36x hectares. 2. The second combine harvested 3/4 of the remaining area. The remaining area after the first combine is (1 - 0.36)x hectares. So, the second combine harvested (3/4)(1 - 0.36)x hectares. 3. The third combine harvested 8 hectares less than the second combine. So, the third combine harvested [(3/4)(1 - 0.36)x - 8] hectares.

To find the values of x, the total area, and the hectares harvested by each combine, we need to solve the following equation:

0.36x + (3/4)(1 - 0.36)x + 8 = x

Let's solve this equation:

0.36x + (3/4)(1 - 0.36)x + 8 = x

Simplifying the equation:

0.36x + (3/4)(0.64)x + 8 = x

0.36x + 0.48x + 8 = x

0.84x + 8 = x

0.84x - x = -8

-0.16x = -8

x = -8 / -0.16

x = 50

Therefore, the total area of the wheat field is 50 hectares.

Now, let's calculate the hectares harvested by each combine:

1. The first combine harvested 0.36 of the total area, which is 0.36 * 50 = 18 hectares. 2. The second combine harvested 3/4 of the remaining area. The remaining area after the first combine is (1 - 0.36) * 50 = 32 hectares. So, the second combine harvested (3/4) * 32 = 24 hectares. 3. The third combine harvested 8 hectares less than the second combine. So, the third combine harvested 24 - 8 = 16 hectares.

Therefore, the hectares harvested by each combine are as follows: - The first combine harvested 18 hectares. - The second combine harvested 24 hectares. - The third combine harvested 16 hectares.

Answer: - The first combine harvested 18 hectares. - The second combine harvested 24 hectares. - The third combine harvested 16 hectares.

Problem 2: Посадка деревьев пионерами

According to the problem statement, there were three squads of pioneers involved in planting trees. The first squad planted 36% of all the trees, the second squad planted 8/9 of what the first squad planted, and the third squad planted all the remaining trees. The first squad planted 10 more trees than the third squad.

To find out how many trees each squad planted, let's solve the problem step by step.

Let's assume the total number of trees planted is x trees.

1. The first squad planted 36% of all the trees, which is 0.36x trees. 2. The second squad planted 8/9 of what the first squad planted. So, the second squad planted (8/9)(0.36x) trees. 3. The third squad planted all the remaining trees. The remaining trees after the first and second squads planted are (1 - 0.36 - (8/9)(0.36))x trees. So, the third squad planted (1 - 0.36 - (8/9)(0.36))x trees.

To find the value of x, the total number of trees, and the number of trees planted by each squad, we need to solve the following equation:

0.36x + (8/9)(0.36x) + (1 - 0.36 - (8/9)(0.36))x = x - 10

Let's solve this equation:

0.36x + (8/9)(0.36x) + (1 - 0.36 - (8/9)(0.36))x = x - 10

Simplifying the equation:

0.36x + (8/9)(0.36x) + (1 - 0.36 - (8/9)(0.36))x = x - 10

0.36x + (8/9)(0.36x) + (1 - 0.36 - 0.32)x = x - 10

0.36x + (8/9)(0.36x) + (0.68 - 0.36)x = x - 10

0.36x + (8/9)(0.36x) + 0.32x = x - 10

0.36x + 0.32x + (8/9)(0.36x) = x - 10

0.68x + (8/9)(0.36x) = x - 10

0.68x + (8/9)(0.36x) - x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/9)(0.36x) - (9/9)x = -10

0.68x + (8/

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