
Из кассы выдали сначала 3/8 бывших в ней денег, потом 3/5 оставшихся, после этого в кассе осталось
20000 рубдей. Сколько денегбыло в кассе первоначально?

Ответы на вопрос

Первоначально выдали 3/8, значит осталось 5/8 (8/8-3/8), что соответствует 50.000 руб. (как мы посчитали). Тогда первоначально было 50.000/5*8=80.000 рублей



Problem Analysis
To solve this problem, we need to determine the initial amount of money in the cash register. We are given that 3/8 of the money was taken out first, followed by 3/5 of the remaining amount. After these two withdrawals, there was 20,000 rubles left in the cash register.Solution
Let's assume the initial amount of money in the cash register is x rubles.1. The first withdrawal: 3/8 of the money was taken out. This means (3/8)x rubles were withdrawn. 2. After the first withdrawal, the remaining amount of money in the cash register is x - (3/8)x = (5/8)x rubles. 3. The second withdrawal: 3/5 of the remaining amount was taken out. This means (3/5) * (5/8)x = (3/8)x rubles were withdrawn. 4. After the second withdrawal, the remaining amount of money in the cash register is (5/8)x - (3/8)x = (2/8)x rubles, which is equal to 20,000 rubles according to the given information.
Now we can set up an equation to solve for x:
(2/8)x = 20,000
To solve for x, we can multiply both sides of the equation by 8/2:
x = 20,000 * (8/2)
Simplifying the equation:
x = 80,000
Therefore, the initial amount of money in the cash register was 80,000 rubles.
Answer
The initial amount of money in the cash register was 80,000 rubles.

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