Question

Ахиллес бежит за черепахой со скоростью 3 м/с. Между ними 100м. На какой по счёту секунде Ахилл догонит черепаху, которая ползёт в сто раз медленнее,чем бежит Ахилл.

Answer 1

3/100=0,3 м/с - скорость черепахи

3-0,03=2,97 - скорость сближения

100/2,97=297 с=4 мин57 сек - время встречи

Answer 2

Problem Statement

The problem states that Achilles is chasing a tortoise with a speed of 3 m/s. The distance between them is 100 m. The tortoise is crawling at a speed that is 100 times slower than Achilles. The question is, at which second will Achilles catch up to the tortoise?

Solution

To solve this problem, we need to determine the time it takes for Achilles to cover the 100 m distance while the tortoise is moving at a slower speed. Since the tortoise is moving at 1/100th of Achilles' speed, its speed can be calculated as 3 m/s divided by 100, which is 0.03 m/s.

Let's calculate the time it takes for Achilles to catch up to the tortoise.

The formula to calculate time is:

Time = Distance / Speed

For Achilles: Distance = 100 m Speed = 3 m/s

For the tortoise: Distance = 100 m Speed = 0.03 m/s

Let's calculate the time it takes for Achilles to catch up to the tortoise.

Time = Distance / Speed

For Achilles: Time = 100 m / 3 m/s

For the tortoise: Time = 100 m / 0.03 m/s

Calculating the time for Achilles:

Time = 100 m / 3 m/s = 33.33 seconds

Calculating the time for the tortoise:

Time = 100 m / 0.03 m/s = 3333.33 seconds

Therefore, Achilles will catch up to the tortoise at approximately 33.33 seconds.

Please note that the above calculations assume constant speeds for both Achilles and the tortoise. In reality, the speeds may vary, and this problem simplifies the scenario for calculation purposes.

Answer

Achilles will catch up to the tortoise at approximately 33.33 seconds.

Please let me know if there is anything else I can help you with.