Question

Данные величины Запишите с точностью до одного килограмма с недостатком и с избытком и с управлением 5 килограмм 768г. 9кг 326г. 4ц 36кг 125г. 5т 7ц

Answer 1

5,768 кг ~ 5 с недостатком или 6 с избытком 
9.326 ~ 9 или 10
436 кг  = 4,360 ц 
5700 кг = 5,700 т
.

Answer 2

I can answer your question in detail. You want to write the given quantities with an accuracy of one kilogram with a deficiency and with an excess and with rounding. Here are the answers:

- 5 kilograms 768 grams - with a deficiency: 5 kilograms - with an excess: 6 kilograms - with rounding: 6 kilograms - 9 kilograms 326 grams - with a deficiency: 9 kilograms - with an excess: 10 kilograms - with rounding: 9 kilograms - 4 centners 36 kilograms 125 grams - with a deficiency: 436 kilograms - with an excess: 437 kilograms - with rounding: 436 kilograms - 5 tons 7 centners - with a deficiency: 5070 kilograms - with an excess: 5080 kilograms - with rounding: 5070 kilograms

I hope this helps you.

If you want to learn more about how to write quantities with different accuracies, you can check out these web pages:

- [Упр.525 ГДЗ Никольский Потапов 5 класс по математике](https://reshak.ru/otvet/reshebniki.php?otvet=525&predmet=nikol5) - [Упр.388 ГДЗ Никольский Потапов 5 класс по математике](https://reshak.ru/otvet/reshebniki.php?otvet=388&predmet=nikol5) - [525. ГДЗ Математика 5 класс Никольский. Помогите записать с точностью до кг](https://class.rambler.ru/temy-gdz/525-gdz-matematika-5-klass-nikolskiy-pomogite-zapisat-s-tochnostyu-do-kg-59320.htm)