Question

Помогите решить задачу . За 2 год роботи трактора витратив а л пального.На скільки годин роботи вистачить йому 56 л пального, якщо витрата пального загодину однакова ? Склади вираз для розвязуванння задачі та обчисли його значення, якщо а=14.

Answer 1

А/2 л/ч- расход топлива в час
56:а/2=56*2/а=112/а на столько часов роботи вистачить йому 56 л пального

При а=14
112/14=8 - на 8 часов

Answer 2

To solve this problem, we need to find out how many hours the tractor can work with 56 liters of fuel, given that the fuel consumption per hour is constant.

Let's denote the number of hours the tractor can work as h.

We know that in 2 years (which is equivalent to 24 months or 730 days), the tractor consumed a liters of fuel.

Using the given information, we can set up the following equation:

2 * 365 * h = a

Substituting the given value of a = 14, we can solve for h:

2 * 365 * h = 14

Simplifying the equation:

730h = 14

Dividing both sides of the equation by 730:

h = 14 / 730

Now, let's calculate the value of h:

h ≈ 0.0192 (rounded to four decimal places)

Therefore, the tractor can work for approximately 0.0192 hours (or 1.152 minutes) with 56 liters of fuel, given that the fuel consumption per hour is constant.

I hope this helps! Let me know if you have any further questions.