Question

24 қызыл шар 42 көк және 30 сары шардан бірнеше тізбе дайндалды. Тізбелердегі қызыл,көк,сары шарлардың саны бірдей. Ең көп дегенде нещ

Answer 1

6 shar kerek .sebebi 24,42,30 6-ga bolinedi

Answer 2

I will try to answer your question in detail. You have 24 red balls, 42 blue balls and 30 yellow balls, and you want to make some sets of balls. Each set must have the same number of red, blue and yellow balls. How many sets can you make at most?

To answer this question, we need to find the greatest common divisor (GCD) of the numbers 24, 42 and 30. The GCD is the largest positive integer that divides all the given numbers without leaving a remainder. One way to find the GCD is to use the Euclidean algorithm, which is based on the following property: if a and b are positive integers, and a = bq + r, where q and r are the quotient and remainder of dividing a by b, then GCD(a, b) = GCD(b, r).

Using this algorithm, we can find the GCD of 24, 42 and 30 as follows:

- First, we divide 42 by 24 and get the quotient 1 and the remainder 18. So, GCD(42, 24) = GCD(24, 18). - Next, we divide 24 by 18 and get the quotient 1 and the remainder 6. So, GCD(24, 18) = GCD(18, 6). - Then, we divide 18 by 6 and get the quotient 3 and the remainder 0. So, GCD(18, 6) = GCD(6, 0). - Finally, we see that the remainder is 0, which means that 6 is the GCD of 42 and 24. So, GCD(42, 24) = 6.

Now, we need to find the GCD of 6 and 30. We can use the same algorithm as before:

- First, we divide 30 by 6 and get the quotient 5 and the remainder 0. So, GCD(30, 6) = GCD(6, 0). - Then, we see that the remainder is 0, which means that 6 is the GCD of 30 and 6. So, GCD(30, 6) = 6.

Therefore, the GCD of 24, 42 and 30 is 6. This means that we can make 6 sets of balls, each with 4 red balls, 7 blue balls and 5 yellow balls. This is the maximum number of sets we can make, because if we try to make more sets, we will not have enough balls of some color. For example, if we try to make 7 sets, we will need 28 red balls, but we only have 24.