Question

Дана функция y=f(x). Найдите: угловой коэффициент касательной к графику этои функции в точке с абсциссой x0. Помогите

Answer 1

1) Необходимо найти производную функции
2) В полученное выражение вместо Х вставить значение Хо
3) Это и есть ответ.

Например:
Xo = 5
Y = X²
Y' = 2*X
k = 2*5 = 10
Всё!

Answer 2

Finding the Slope of the Tangent Line

To find the slope of the tangent line to the graph of the function y = f(x) at the point with the abscissa x0, we can use the derivative of the function. The slope of the tangent line at a point x0 is given by the derivative of the function evaluated at x0, denoted as f'(x0).

The derivative of the function y = f(x) is denoted as f'(x), and the slope of the tangent line at x0 is given by f'(x0).

Using the provided search results, we can find the derivative of the function and evaluate it at x0 to find the slope of the tangent line.

Calculating the Slope

The derivative of the function y = f(x) is denoted as f'(x). From the search results, we have the following information: - The derivative of the function at x0 is denoted as f'(x0). - The derivative of the function is given by f'(x) = 2*x - 1.

Now, we can calculate the slope of the tangent line at x0: - f'(x0) = 2*x0 - 1

Given x0 = -2, we can substitute this value into the derivative to find the slope of the tangent line at x0.

Result

Substituting x0 = -2 into the derivative f'(x) = 2*x - 1: - f'(-2) = 2*(-2) - 1 - f'(-2) = -4 - 1 - f'(-2) = -5

The slope of the tangent line to the graph of the function y = f(x) at the point with the abscissa x0 = -2 is -5.

I hope this helps! If you have further questions or need additional assistance, feel free to ask.