Question

Одна сторона прямаугольника в 4 раза меньше другой периметр его 131 дм. Вычисли стороны прямяугольника

Answer 1

P=a+b+c+d (периметр это сумма длин всех сторон)
В прямоугольнике периметр это P=2a+2b
пусть сторона а будет х, тогда b будет 4х
Получаем уравнение
2х+2(4х)=131(дм)
2х+8х=131
10х=131
х=131÷10
х=13.1(дм) - сторона а,
значит сторона b - х·4 = 13.1·4= 52.4(дм)

Ответ: стороны прямоугольника 13.1 и 52.4 дм.

Answer 2

(х+4х)*2=131
2х+8х=131
10х=131
х=131:10
х=13.1дм одна сторона

13.1*4=52.4 дм другая сторона

Answer 3

Understanding the problem

We are given that one side of a rectangle is 4 times smaller than the other side. The perimeter of the rectangle is given as 131 dm. We need to calculate the lengths of the sides of the rectangle.

Solution

Let's assume the length of the longer side of the rectangle is "x" dm. Since the other side is 4 times smaller, the length of the shorter side will be x/4 dm.

The perimeter of a rectangle is given by the formula: Perimeter = 2 * (Length + Width)

Given that the perimeter is 131 dm, we can write the equation as: 131 = 2 * (x + x/4)

Simplifying the equation: 131 = 2 * (5x/4) Dividing both sides by 2: 65.5 = 5x/4 Multiplying both sides by 4: 262 = 5x Dividing both sides by 5: x = 52.4

So, the longer side of the rectangle is 52.4 dm, and the shorter side is 52.4/4 = 13.1 dm.

Therefore, the lengths of the sides of the rectangle are approximately 52.4 dm and 13.1 dm.