Question

В 11 часов с аэродрома вылетели одновременно в противоположных направлениях два самолета. в 14 часов расстояние между ними было 3540км. один из них летел со скоростью 620 км\ч. с какой средней скоростью летел другой самолет?

Answer 1

1) 14 - 11 = 3(часа) были в полёте самолёты
2) 620 * 3 = 1860(км) пролетел 1-ый самолёт
3) 3540 - 1860 = 1680(км) пролетел 2-ой самолёт
4) 1680 : 3 = 560(км/ч)
Ответ: 560км/ч - средняя скорость 2-ого самолёта.

Answer 2

Calculation of the Average Speed of the Second Plane

To find the average speed of the second plane, we can use the information provided in the question.

According to the question, two planes took off simultaneously in opposite directions from an airport at 11:00. At 14:00, the distance between them was 3540 km. One of the planes was flying at a speed of 620 km/h.

To calculate the average speed of the second plane, we can follow these steps:

1. Calculate the time difference between the takeoff and the given time (14:00). In this case, the time difference is 3 hours.

2. Calculate the distance covered by the first plane in the given time. Since the first plane was flying at a speed of 620 km/h for 3 hours, the distance covered by the first plane is 620 km/h * 3 hours = 1860 km.

3. Subtract the distance covered by the first plane from the total distance between the two planes. In this case, the total distance is 3540 km, and the distance covered by the first plane is 1860 km. Therefore, the remaining distance between the two planes is 3540 km - 1860 km = 1680 km.

4. Divide the remaining distance by the time difference to find the average speed of the second plane. In this case, the remaining distance is 1680 km, and the time difference is 3 hours. Therefore, the average speed of the second plane is 1680 km / 3 hours = 560 km/h.

So, the second plane was flying with an average speed of 560 km/h.

Please let me know if there's anything else I can help you with!