Question

От мотка провода отрезали сначала 30% , а затем еще 60% остатка. После этого в мотке осталось 42 метров провода сколько метров провода было в мотке первоначально?

Answer 1

520 метров в мотке проволки было

Answer 2

Problem Analysis

We are given that a wire was initially cut by 30% and then by an additional 60% of the remaining length. After these two cuts, there are 42 meters of wire left in the coil. We need to determine the initial length of the wire in the coil.

Solution

Let's assume the initial length of the wire in the coil is x meters.

The first cut removes 30% of the wire, leaving 70% of the wire remaining. This can be calculated as 0.7x meters.

The second cut removes 60% of the remaining wire, which is equivalent to 42 meters. We can set up the following equation to represent this:

0.4(0.7x) = 42

Simplifying the equation, we have:

0.28x = 42

To solve for x, we divide both sides of the equation by 0.28:

x = 42 / 0.28

Evaluating the expression, we find:

x = 150

Therefore, the initial length of the wire in the coil was 150 meters.

Answer

The initial length of the wire in the coil was 150 meters.