Question

Помогите решить задачу с полным расписом. Из города А в город С вылетел самолет. Через 2,7 часов он совершил посадку в город В, в котором находился 48 минут. Затем он взлетел и через 2,6 часа он долетел до города С. Через сколько часов самолет долетел из города А в город С. Зарание спамибо

Answer 1

2,7 ч = 2,7 * 60 = 162 мин - летел самолёт до города В

2,6 ч = 2,6 * 60 = 156 мин - летел самолёт до города С из города В

162 мин + 48 мин + 156 мин = 364 мин - самолёт летел до города С из города А (мы сложили время всего пути (2,7 ч и 2,6 ч) и остановки (48 мин)

364 мин = 364 : 60 =  ч - весь путь в часах

Ответ:  6,1 часов

Answer 2

Problem Analysis

To solve this problem, we need to calculate the total time it took for the plane to travel from city A to city C. We have the following information: - The plane flew from city A to city B and landed after 2.7 hours, staying for 48 minutes. - After taking off from city B, it flew for 2.6 hours to reach city C.

Solution

Let's calculate the total time it took for the plane to travel from city A to city C.

The total time can be calculated as the sum of the time taken for the first leg of the journey (from A to B), the time spent on the ground in city B, and the time taken for the second leg of the journey (from B to C).

The time taken for the first leg of the journey is 2.7 hours, the time spent on the ground in city B is 48 minutes (or 0.8 hours), and the time taken for the second leg of the journey is 2.6 hours.

So, the total time taken for the journey from city A to city C is: Total Time = Time from A to B + Time on ground in B + Time from B to C

Total Time = 2.7 hours + 0.8 hours + 2.6 hours

Total Time = 6.1 hours

Therefore, the plane took a total of 6.1 hours to travel from city A to city C.

Final Answer

The plane took 6.1 hours to travel from city A to city C.