Question

Ширина прямоугольника на 54 см мельше длины.Найдите периметр прямоугольника,если его длина в 7 раз больше ширины. Пожалуйста помогите решить задачу!

Answer 1

7,5- ширина
15- вся ширина
54-15=39-это общая длина
то 39:2=18,5- одна длина
значит: 7,5+7,5+18,5+18,5=54

Answer 2

7,5- ширина
15- вся ширина
54-15=39-это общая длина
то 39:2=18,5- одна длина
значит: 7,5+7,5+18,5+18,5=54
так?

Answer 3

Problem Analysis

We are given that the width of a rectangle is 54 cm less than its length. We are also told that the length is 7 times greater than the width. We need to find the perimeter of the rectangle.

Solution

Let's assume the width of the rectangle is w cm. According to the problem, the length of the rectangle is 7 times greater than the width, so the length would be 7w cm.

We are also given that the width is 54 cm less than the length. So we can write the equation:

7w - 54 = w

Now, let's solve this equation to find the value of w.

7w - w = 54

6w = 54

w = 9

So the width of the rectangle is 9 cm.

Now, we can find the length of the rectangle:

Length = 7w = 7 * 9 = 63 cm

To find the perimeter of the rectangle, we can use the formula:

Perimeter = 2 * (Length + Width)

Substituting the values:

Perimeter = 2 * (63 + 9) = 2 * 72 = 144 cm

Therefore, the perimeter of the rectangle is 144 cm.

Answer

The perimeter of the rectangle is 144 cm.