Question

На стоянке грузовых машин в 4 раза меньше,чем легковых. Легковых машин на 15 больше,чем грузовых. Сколько грузовых машин на стоянке и сколько легковых? Схематический чертёж поможет тебе решить задачу. 2 класс,уравнениями они не решают

Answer 1

15÷3=5 (шт) грузовиков
5×4=20 (шт) легковых

Answer 2

4-1=3                                                                                                                    

15:3=5 (грузовых)                                                                                                    
15+5=20(легковых)                                                                                               Ответ:20.              

Answer 3

Problem Analysis

To solve this problem, we need to find the number of trucks and cars in a parking lot. We are given two pieces of information: 1. The number of trucks is four times less than the number of cars. 2. The number of cars is 15 more than the number of trucks.

Let's assume the number of trucks is represented by T and the number of cars is represented by C.

Solution

Based on the given information, we can set up the following equations:

1. The number of trucks is four times less than the number of cars: T = C - 4C. 2. The number of cars is 15 more than the number of trucks: C = T + 15.

To solve this system of equations, we can substitute the value of C from equation 2 into equation 1:

T = (T + 15) - 4(T + 15).

Simplifying the equation:

T = T + 15 - 4T - 60.

Combining like terms:

T = -3T - 45.

Adding 3T to both sides:

4T = -45.

Dividing both sides by 4:

T = -45/4.

Since the number of trucks cannot be negative, we can conclude that there are no trucks in the parking lot.

To find the number of cars, we can substitute the value of T into equation 2:

C = -45/4 + 15.

Simplifying the equation:

C = -45/4 + 60/4.

Combining like terms:

C = 15/4.

Therefore, there are 15/4 or 3.75 cars in the parking lot.

Answer

There are no trucks and 3.75 cars in the parking lot.

Please note that the number of cars cannot be a fraction, so it is likely that there is a mistake in the given information or the problem itself.