Question

Помогите решить задачу Мише вместе с папой 42 года ,его брату Саше вместе с папой 40 лет ,а всем им вместе 50 лет . Узнай сколько лет каждому из них !! Ребята я задачу решил просто вас проверяю

Answer 1

1)50-42=8(лет)-саше

2)50-40=10(лет)-мише

3)42-10=32(лет папе

Ответ:8 лет,10лет,32года

Answer 2

Problem Analysis

We are given the ages of three individuals: Misha, his brother Sasha, and their father. The sum of Misha's age and his father's age is 42 years. The sum of Sasha's age and his father's age is 40 years. The sum of the ages of all three individuals is 50 years. We need to determine the age of each person.

Solution

Let's assign variables to represent the ages of Misha, Sasha, and their father. We'll use the following variables: - Misha's age: M - Sasha's age: S - Father's age: F

From the given information, we can write the following equations: 1. M + F = 42 2. S + F = 40 3. M + S + F = 50

To solve this system of equations, we can use substitution or elimination. Let's use the elimination method.

Adding equations 1 and 2, we get: (M + F) + (S + F) = 42 + 40 M + S + 2F = 82

Subtracting equation 3 from this result, we get: (M + S + 2F) - (M + S + F) = 82 - 50 F = 32

Now, we can substitute the value of F into equations 1 and 2 to find the ages of Misha and Sasha.

From equation 1: M + 32 = 42 M = 42 - 32 M = 10

From equation 2: S + 32 = 40 S = 40 - 32 S = 8

Therefore, Misha is 10 years old, Sasha is 8 years old, and their father is 32 years old.

Answer

Misha is 10 years old, Sasha is 8 years old, and their father is 32 years old.