Question

Задача... В двух автоцистернах 32 т бензина. Количества бензина первой цистерны составляло 7/9 количества бензина второй цистерны. Сколько тонн бензина было в каждой из этих двух автоцистерны?

Answer 1

1 цистерна - 7/9х т2 цистерна - х т х+х=32х=3216х=32*916х=288х=288:16х=18 т - во 2 цистерне7/9х==14 т - в 1 цистерне
Проверка:18+14=32

Answer 2

Problem Analysis

We are given two tanker trucks carrying a total of 32 tons of gasoline. The amount of gasoline in the first tanker truck is 7/9 of the amount in the second tanker truck. We need to determine the amount of gasoline in each of the two tanker trucks.

Solution

Let's assume the amount of gasoline in the second tanker truck is x tons. According to the problem, the amount of gasoline in the first tanker truck is 7/9 of x.

To solve for x, we can set up the following equation:

(7/9)x + x = 32

Now, let's solve for x.

Calculation

(7/9)x + x = 32

To simplify the equation, let's find a common denominator for the fractions:

(7/9)x + (9/9)x = 32

Now, we can combine the fractions:

(16/9)x = 32

To isolate x, we can multiply both sides of the equation by the reciprocal of (16/9), which is (9/16):

x = (32 * 9/16)

Now, let's calculate the value of x:

x = (32 * 9/16) = 18

Therefore, the amount of gasoline in the second tanker truck is 18 tons.

To find the amount of gasoline in the first tanker truck, we can substitute the value of x into the equation:

(7/9)x = (7/9) * 18 = 14

Therefore, the amount of gasoline in the first tanker truck is 14 tons.

Answer

The amount of gasoline in each of the two tanker trucks is as follows: - The first tanker truck contains 14 tons of gasoline. - The second tanker truck contains 18 tons of gasoline.