Question

1-й авто перевозит 300 брикетов за 6 рейсов,а 2-й за 3 рейса.За сколько рейсов смогут перевезти все брикеты оба авто,если будут работать вместе?

Answer 1

1-ое: 1/6
2-ое: 1/3
(1/6)+(1/3)= 1/2
1: (1/2)= 2.
За 2 рейса.

Answer 2

Problem Analysis

We are given two cars, where the first car can transport 300 briquettes in 6 trips, and the second car can transport 300 briquettes in 3 trips. We need to determine how many trips it will take for both cars to transport all the briquettes if they work together.

Solution

To find the number of trips required for both cars to transport all the briquettes, we need to calculate the least common multiple (LCM) of the number of trips for each car.

The LCM is the smallest positive integer that is divisible by both numbers. In this case, we need to find the LCM of 6 and 3.

The LCM of 6 and 3 is 6, as it is the smallest number that is divisible by both 6 and 3.

Therefore, it will take both cars 6 trips to transport all the briquettes if they work together.

Answer

If both cars work together, it will take them 6 trips to transport all the briquettes.

Explanation

The first car can transport 300 briquettes in 6 trips, which means it transports 50 briquettes per trip. Similarly, the second car can transport 300 briquettes in 3 trips, which means it also transports 100 briquettes per trip.

When both cars work together, the total number of briquettes transported per trip is the sum of the briquettes transported by each car. In this case, it is 50 + 100 = 150 briquettes per trip.

Since there are a total of 300 briquettes to be transported, we can calculate the number of trips required by dividing the total number of briquettes by the number of briquettes transported per trip: 300 / 150 = 2 trips.

However, since we are considering the number of trips for both cars working together, we need to find the LCM of the number of trips for each car, which is 6.

Therefore, it will take both cars 6 trips to transport all the briquettes if they work together.