Question

Теплоход был в плавании в один день 16 часов ,а в другой 20 часов и шёл все время с одинаковой скоростью . В первый лень он прошёл на 112 км меньше ,чем во второй . Сколько всего километров прошёл теплоход за два дня?

Answer 1

20-16=4 ч
20+16=36 ч
112/4=28 км/ч скорость
28*36==1008 км всего

Answer 2

20 - 16 = 4 ч разница
112 : 4 = 28 км/ч скорость
28 • (20 + 16) = 28 • 36 = 1008 км прошел теплоход за 2 дня

Answer 3

Problem Analysis

We are given that a ship traveled for 16 hours on one day and 20 hours on another day, both at the same constant speed. The ship traveled 112 km less on the first day compared to the second day. We need to find the total distance traveled by the ship over the two days.

Solution

Let's assume the ship's speed is v km/h.

On the first day, the ship traveled for 16 hours at a speed of v km/h. Therefore, the distance traveled on the first day is 16v km.

On the second day, the ship traveled for 20 hours at the same speed of v km/h. Therefore, the distance traveled on the second day is 20v km.

We are given that the ship traveled 112 km less on the first day compared to the second day. So, we can set up the following equation:

20v - 16v = 112

Simplifying the equation, we get:

4v = 112

Dividing both sides of the equation by 4, we find:

v = 28

Now that we know the speed of the ship is 28 km/h, we can calculate the total distance traveled over the two days:

Total distance = Distance on first day + Distance on second day = 16v + 20v = 36v = 36 * 28 = 1008 km

Therefore, the ship traveled a total of 1008 km over the two days.

Answer

The ship traveled a total of 1008 km over the two days.