Question

Сплав состоит из свинца и олова . На 5 частей олова выходит 2 части свинца .1.сколько граммов олова содержит сплав в котором 70граммов свинца задача по математике

Answer 1

Х/5=70/2
2х=350
х=175 гр

Answer 2

5:2=2,5 олова больше
70*2,5=175 гр олова   

ну или так
70:2=35 гр идет на одну часть
35*5=175 гр  олова                   

Answer 3

Problem Analysis

We are given that an alloy consists of lead and tin, and the ratio of tin to lead is 5:2. We need to determine the amount of tin in the alloy when there is 70 grams of lead.

Solution

To solve this problem, we can set up a proportion using the given ratio and the known amount of lead.

Let's assume that the amount of tin in the alloy is represented by x grams.

The ratio of tin to lead is given as 5:2, which can be written as:

tin : lead = 5 : 2

We can set up the proportion:

x grams of tin : 70 grams of lead = 5 : 2

To solve for x, we can cross-multiply and solve for x:

x = (70 grams of lead * 5 grams of tin) / 2

Now we can calculate the value of x.

Calculation

Let's substitute the given values into the equation and calculate the amount of tin in the alloy.

x = (70 grams * 5 grams) / 2

x = (350 grams) / 2

x = 175 grams

Answer

Therefore, the alloy contains 175 grams of tin when there are 70 grams of lead.

Please let me know if I can help you with anything else.