Question

Приведите подобные слагаемые:а) 14а + 23а; б)15а -11а; в) -3+3а; г) 6b - 5a д) 32a -a; е)a +19a

Answer 1

А) 14а + 23а; 15а -11а; 3а 5 32a -a;a a +19a

Answer 2

а) 14а + 23а

To find the sum of similar terms, we add the coefficients and keep the variable the same. In this case, the variable is "а".

Adding the coefficients 14 and 23, we get 37. So the sum of 14а + 23а is 37а.

б) 15а - 11а

Similar to the previous example, we add the coefficients and keep the variable the same.

Subtracting 11а from 15а, we get 4а. So the sum of 15а - 11а is 4а.

в) -3 + 3а

In this case, we have a constant term (-3) and a term with a variable (3а). Since these two terms have different types, we cannot combine them.

So, the sum of -3 + 3а cannot be simplified further.

г) 6b - 5a

Similar to the previous examples, we add the coefficients of the terms with the same variable.

The sum of 6b - 5a cannot be simplified further because the terms have different variables.

д) 32а - a

In this case, we have two terms with the same variable "а". We subtract the coefficients and keep the variable the same.

Subtracting "a" from 32а, we get 31а. So the sum of 32а - a is 31а.

е) a + 19а

Here, we have two terms with the same variable "а". We add the coefficients and keep the variable the same.

Adding "a" and 19а, we get 20а. So the sum of a + 19а is 20а.

To summarize: - а) 14а + 23а = 37а - б) 15а - 11а = 4а - в) -3 + 3а = -3 + 3а - г) 6b - 5a = 6b - 5a - д) 32а - a = 31а - е) a + 19а = 20а