Question

Дано: прямоугольник. а-18см,в-в2 раза меньше.Найти P и S ПРЯМОУГОЛЬНИКА

Answer 1

18:2=9 см ширина прямоугольника
P=2(a+b)
a=18 см b=9см

Answer 2

1) 18:2=9(см)- ширина.
2) (18+9)*2=54(см)- Р.
3) 18*9=162(см2)- S.
Ответ: 54 см, 162 см2.

Answer 3

Problem Analysis

We are given a rectangle with one side measuring 18 cm and the other side being 2 times smaller. We need to find the perimeter (P) and the area (S) of the rectangle.

Solution

To find the perimeter of a rectangle, we add up the lengths of all four sides. In this case, we have one side measuring 18 cm and the other side being 2 times smaller. Let's denote the smaller side as 'b'. Since the other side is 2 times smaller, we can write it as 'b = 18/2 = 9 cm'. The perimeter (P) can be calculated as:

P = 2(a + b), where 'a' is the longer side and 'b' is the shorter side.

To find the area of a rectangle, we multiply the lengths of its two adjacent sides. In this case, the longer side is 'a' and the shorter side is 'b'. The area (S) can be calculated as:

S = a * b

Let's substitute the values and calculate the perimeter and area of the rectangle.

Calculation

Given: - Longer side (a) = 18 cm - Shorter side (b) = 9 cm

Perimeter (P) = 2(a + b) = 2(18 + 9) = 2(27) = 54 cm

Area (S) = a * b = 18 * 9 = 162 cm²

Therefore, the perimeter of the rectangle is 54 cm and the area is 162 cm².

Answer

The perimeter of the rectangle is 54 cm and the area is 162 cm².

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