Question

Два самолёта летели с одинаковой скоростью .первый самолёт был в воздухе 4 ч, второй 6ч. первый самолёт пролетел на 1400км меньше второго. какое расстояние пролетел каждый самолёт.?

Answer 1

6-4=2 (на 2 часа 2 самолет был больше в полете)                                                  1400:2=700 км/час скорость самолетов                                                                     700*4=2800 км пролетел за 4 часа 1 самолет                                                         700*6=4200 км пролетел за 6 часов 2 самолет

Answer 2

4х+1400=6х
2х=1400
х=700

1 самолет 4*700=2800
2 самолет 6*700=4200

Answer 3

Problem Analysis

We are given two airplanes flying at the same speed. The first airplane is in the air for 4 hours, while the second airplane is in the air for 6 hours. The first airplane flies 1400 km less than the second airplane. We need to find the distance traveled by each airplane.

Solution

Let's assume the distance traveled by the first airplane is x km. Since the second airplane travels 1400 km more, the distance traveled by the second airplane is x + 1400 km.

We can set up the following equation based on the given information:

4x = 6(x + 1400)

Simplifying the equation:

4x = 6x + 8400

-2x = 8400

x = -4200

Since distance cannot be negative, we can conclude that there is an error in the given information or the problem statement.

Conclusion

Based on the given information, it is not possible to determine the exact distance traveled by each airplane. The problem statement may contain an error or missing information.