Question

От двух пристаней одновременно навстречу друг другу отплыли два катера. Через 5 ч они встретились. С какой скоростью шел каждый катер, если скорость одного на 12 миль/ч больше скорости другого, а расстояние между пристанями 440 миль?

Answer 1

х-скорость одного катера, х+12-скорость второго, х+х+12=2х+12-скорость сближения

5(2х+12)-путь пройденный двумя катерами

5(2х+12)=440

10х+60=440

10х=440-60=380

х=380/10=38 миль/ч-скорость одного катера

38+12=50 миль/ч-скорость второго

Answer 2

5(2х+12)-путь пройденный двумя катерами

5(2х+12)=440

10х+60=440

10х=440-60=380

х=380:10=38 V1

38+12=50миль/час V2

Answer 3

Problem Analysis

We have two boats that set sail from two different piers simultaneously and meet each other after 5 hours. The speed of one boat is 12 miles per hour faster than the speed of the other boat, and the distance between the piers is 440 miles. We need to find the speed of each boat.

Solution

Let's assume the speed of the slower boat is x miles per hour. Therefore, the speed of the faster boat will be x + 12 miles per hour.

We can use the formula distance = speed × time to calculate the distance traveled by each boat.

The slower boat travels for 5 hours at a speed of x miles per hour, so the distance it covers is 5x miles.

The faster boat travels for 5 hours at a speed of x + 12 miles per hour, so the distance it covers is 5(x + 12) miles.

Since the total distance between the piers is 440 miles, we can set up the following equation:

5x + 5(x + 12) = 440

Simplifying the equation:

5x + 5x + 60 = 440

10x + 60 = 440

10x = 380

x = 38

Therefore, the speed of the slower boat is 38 miles per hour, and the speed of the faster boat is 38 + 12 = 50 miles per hour.

Answer

The slower boat was traveling at a speed of 38 miles per hour, and the faster boat was traveling at a speed of 50 miles per hour.