Question

вероятность попадания в цель первым стрелком равна 0,8, а вторым 0,7. Стрелки делают по одному выстрелу по цели одновременно.Определить вероятность того, что цель будет поражена, если стрелки стреляют независимо друг от друга

Answer 1

P(A+B) = P(A) + P(B) — P(AB)

0,8+0,7-0,8*0,7=0,94

Ответ   0,94

Answer 2

Problem Analysis

We are given that the probability of hitting the target by the first shooter is 0.8, and the probability of hitting the target by the second shooter is 0.7. The shooters fire simultaneously and independently. We need to determine the probability that the target will be hit.

Solution

To find the probability that the target will be hit, we can use the principle of complementary probability. We will find the probability that both shooters miss the target and subtract it from 1.

Let's denote the probability of hitting the target by the first shooter as p1 (0.8) and the probability of hitting the target by the second shooter as p2 (0.7).

The probability that both shooters miss the target is given by P0 = (1 - p1) * (1 - p2).

Substituting the given values, we have P0 = (1 - 0.8) * (1 - 0.7) = 0.2 * 0.3 = 0.06.

Therefore, the probability that the target will be hit is 1 - P0 = 1 - 0.06 = 0.94.

So, the probability that the target will be hit when the shooters fire independently is 0.94.

Answer

The probability that the target will be hit when the shooters fire independently is 0.94.