Question

Теплоход рассчитан на 980 пассажиров и 30 членовкоманды. Каждая спасательная шлюпка может вместить 50 человек. Какое наименьшее число шлюпок должно быть натеплоходе, чтобы в случае необходимости в них можно былоразместить всех пассажиров и всех членов команды? 3. Решите уравнение: 5⋅( ) ( ) x + 5 − 3 − 2x =1.помогите два задания решить

Answer 1

980+30=1010

1010/50=20,2

[20,2+1]=21

ответ 21 шлюпка

Answer 2

На теплоходе 21 шлюпка, т.к. для размещения всех людей необходимо 

N >= (980+30):50 = 2,2 округляется в большую сторону  21 шлюпка.

Второе уравнение написано не полностью (в скобках ничего нет).

Answer 3

1. To determine the minimum number of lifeboats required to accommodate all passengers and crew members on the ship, we need to divide the total number of people by the capacity of each lifeboat.

Given: - Total number of passengers: 980 - Total number of crew members: 30 - Capacity of each lifeboat: 50

To calculate the minimum number of lifeboats needed, we can use the following formula:

Minimum number of lifeboats = (Total number of passengers + Total number of crew members) / Capacity of each lifeboat

Substituting the given values into the formula:

Minimum number of lifeboats = (980 + 30) / 50

Calculating the result:

Minimum number of lifeboats = 1010 / 50 = 20.2

Since we cannot have a fraction of a lifeboat, we need to round up to the nearest whole number. Therefore, the minimum number of lifeboats required is 21.

2. To solve the equation: 5⋅(x + 5) - 3 - 2x = 1, we can follow these steps:

Step 1: Distribute the multiplication: 5x + 25 - 3 - 2x = 1

Step 2: Combine like terms: (5x - 2x) + (25 - 3) = 1 3x + 22 = 1

Step 3: Move the constant term to the other side of the equation: 3x = 1 - 22 3x = -21

Step 4: Solve for x by dividing both sides by 3: x = -21 / 3 x = -7

Therefore, the solution to the equation is x = -7.