Вопрос задан 06.08.2018 в 13:48. Предмет Математика. Спрашивает Босий Роман.

1)в магазине было несколько десятков метров ткани. после того как 10 м. ткани продали,осталось 40 м

. сколько метров ткани было в магазине? 2)в магазине было 50м танки.после того как несколько десятков метров ткани продали,осталось 40м. Сколько метров ткани продали?3)в магазине было 10м ткани.после того как привезли еще несколько десятков метров,стало 50м ткани.сколько метров ткани привезли в магазин?ОПРЕДЕЛИ И ЗАПИШИ,РЕШЕНИЕМ КАКОЙ ЗАДАЧИ ЯВЛЯЕТСЯ КАЖДОЕ ИЗ УРАВНЕНИЙ, 10+х=50, 50-х=40, х-10=40...НАЙДИ КОРЕНЬ КАЖДОГО УРАВНЕНИЯ.ЗАПИШИ ОТВЕТЫ.
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Отвечает Талипова Руслана.
1)х-10=40
х=40+10
х=50
2)50-х=40
х=50-40
х=10
3)10+х=50
х=50-10
х=40
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Task 1: Finding the Initial Amount of Fabric in the Store

To find the initial amount of fabric in the store, we can use the information provided in the problem statement.

According to the problem, there were several tens of meters of fabric in the store. After selling 10 meters of fabric, there were 40 meters left.

Let's assume the initial amount of fabric in the store is represented by the variable x.

The equation representing the given information can be written as:

x - 10 = 40

To find the value of x, we can solve this equation.

Solution:

x - 10 = 40

Adding 10 to both sides of the equation:

x - 10 + 10 = 40 + 10

x = 50

Therefore, the initial amount of fabric in the store was 50 meters.

Task 2: Finding the Amount of Fabric Sold

To find the amount of fabric sold, we can use the information provided in the problem statement.

According to the problem, there were 50 meters of fabric in the store initially. After selling some tens of meters of fabric, there were 40 meters left.

Let's assume the amount of fabric sold is represented by the variable y.

The equation representing the given information can be written as:

50 - y = 40

To find the value of y, we can solve this equation.

Solution:

50 - y = 40

Subtracting 40 from both sides of the equation:

50 - y - 40 = 40 - 40

10 - y = 0

Adding y to both sides of the equation:

10 - y + y = 0 + y

10 = y

Therefore, the amount of fabric sold was 10 meters.

Task 3: Finding the Amount of Fabric Delivered to the Store

To find the amount of fabric delivered to the store, we can use the information provided in the problem statement.

According to the problem, there were 10 meters of fabric in the store initially. After delivering some tens of meters of fabric, there were 50 meters left.

Let's assume the amount of fabric delivered is represented by the variable z.

The equation representing the given information can be written as:

10 + z = 50

To find the value of z, we can solve this equation.

Solution:

10 + z = 50

Subtracting 10 from both sides of the equation:

10 + z - 10 = 50 - 10

z = 40

Therefore, 40 meters of fabric were delivered to the store.

Summary of Solutions:

1) The initial amount of fabric in the store was 50 meters. 2) The amount of fabric sold was 10 meters. 3) The amount of fabric delivered to the store was 40 meters.

Please let me know if you need any further assistance!

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