Question

Брикет халвы разрезали на три куска в отношении 2:5:7. Самый большой кусок халвы тяжелее самого маленького куска халвы на 2 кг 900г. Найдите массу брикета халвы.

Answer 1

(2+5+7) х = 14х- это весь брикет халвы,
Б. больше на 2кг 900г М., значит 
7х-2х=2кг 900г
5х = 2 кг 900 г 
х= 580 г
Чтобы найти весь кусок халвы нужно
14*580=8120г=8кг 120 г

Answer 2

Problem Analysis

We are given that a halva brick was cut into three pieces in the ratio of 2:5:7. The heaviest piece is 2 kg 900 g more than the lightest piece. We need to find the mass of the halva brick.

Solution

Let's assume the masses of the three pieces of halva are 2x, 5x, and 7x, where x is a constant.

According to the given information, the heaviest piece is 2 kg 900 g more than the lightest piece. This can be expressed as:

7x = 2x + 2 kg 900 g

To solve for x, we can subtract 2x from both sides of the equation:

7x - 2x = 2 kg 900 g

Simplifying the equation:

5x = 2 kg 900 g

Now, we need to convert 2 kg 900 g into a single unit. Since 1 kg = 1000 g, we can convert 2 kg 900 g into grams:

2 kg 900 g = 2,900 g

Substituting this value back into the equation:

5x = 2,900 g

To find the value of x, we can divide both sides of the equation by 5:

x = 2,900 g / 5

Simplifying the equation:

x = 580 g

Now that we have the value of x, we can find the mass of the halva brick by adding the masses of the three pieces:

2x + 5x + 7x = 14x

Substituting the value of x:

14 * 580 g = 8,120 g

Therefore, the mass of the halva brick is 8,120 grams.

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