Question

Два сварщика сделали 48 рам. Один из них работал 7 дней, а другой 9 дней. Сколько рам сделал каждый сварщик, если дневная выработка у них одинаковая? Помогите решить задачу .

Answer 1

48:(7+9)=3(РАМЫ/ДЕНЬ)
7*3=21(РАМА)
9*3=27(РАМ)

Answer 2

Problem Analysis

Two welders made a total of 48 frames. One of them worked for 7 days, and the other worked for 9 days. If their daily output is the same, we need to determine how many frames each welder made.

Solution

Let's denote the number of frames made by the first welder as x and the number of frames made by the second welder as y. We can set up the following system of equations based on the given information: 1. x + y = 48 (total frames made) 2. 7x = 9y (work done in 7 days by the first welder equals the work done in 9 days by the second welder)

Solving the System of Equations

We can solve this system of equations to find the values of x and y.

From equation 2, we can express x in terms of y: x = (9/7)y

Substitute this expression for x into equation 1: (9/7)y + y = 48 16y/7 = 48 y = 48 * 7 / 16 y = 21

Now, we can find x: x = (9/7)y x = (9/7)*21 x = 27

Answer

So, the first welder made 27 frames and the second welder made 21 frames.