Question

В озере водятся караси,окуни и щуки. Два рыбака поймали вместе 70 рыб,причём 5\9 улова первого рыбака - караси,а 7\17 улова второго - окуни. Столько щук поймал каждый,если оба поймали поровну карасей и окуней?

Answer 1

Всего рыб 17+9=28 частей
1 часть = 70\28=2,5
Первый поймал 12,5 карасей(5*2,5)
А второй ((9-5)*2,5=10 карасей

Первый поймал 7*2.5=17.5 окуней
Всего первый поймал 17.5+12.5=30
Второй значит 70-30=40

Answer 2

Problem Analysis

Two fishermen caught a total of 70 fish in a lake. The first fisherman caught 5/9 of the total catch as carp, and the second fisherman caught 7/17 of the total catch as pike. We need to determine how many pike each fisherman caught if they both caught an equal number of carp and pike.

Solution

Let's assume that both fishermen caught x carp and x pike each.

The total number of carp caught by the first fisherman is 5/9 of the total catch, which is equal to (5/9) * 70 = 38.89. Since the number of fish must be a whole number, we can round it to the nearest whole number, which is 39.

The total number of pike caught by the second fisherman is 7/17 of the total catch, which is equal to (7/17) * 70 = 29.41. Again, rounding it to the nearest whole number, we get 29.

Therefore, each fisherman caught 39 carp and 29 pike.

Answer

Each fisherman caught 39 carp and 29 pike.

Explanation

The first fisherman caught 5/9 of the total catch as carp, which is (5/9) * 70 = 38.89. Rounding it to the nearest whole number, we get 39 carp. The second fisherman caught 7/17 of the total catch as pike, which is (7/17) * 70 = 29.41. Rounding it to the nearest whole number, we get 29 pike. Therefore, each fisherman caught 39 carp and 29 pike