Question

Два ребра прямоугольного параллелепипеда, выходящие из одной вершины, равны 5 и 8 см. Площадь его поверхности равна 210 см2 .Найти третье ребро, выходящее из той же вершины

Answer 1

Измерения прямоугольного параллелепипеда:
a=5 см
b=8 см
c=? см

Sполн. пов.=2*(a*b+b*c+a*c)

210=2*(5*8+8*c+5*c), 210=80+26c. 26c=130

c=5 см

Answer 2

Solution:

To find the length of the third edge of the rectangular parallelepiped, we can use the formula for the surface area of a rectangular parallelepiped and the given information about the two edges.

The formula for the surface area of a rectangular parallelepiped is given by: 2*(ab + bc + ac), where a, b, and c are the lengths of the three edges.

Given: - Two edges, a = 5 cm and b = 8 cm. - Surface area = 210 cm^2.

We need to find the length of the third edge, c.

Calculation:

Using the given information and the formula for the surface area, we can set up the equation: 2*(5c + 8c + 40) = 210

Solving for c: 10c + 16c + 80 = 210 26c + 80 = 210 26c = 130 c = 130 / 26 c = 5

Answer:

The length of the third edge, c, coming out of the same vertex is 5 cm.