Question

С КРАТКИМ УСЛОВИЕМ!!!!!!!!!! 10) Реши задачи.Kа) Ученица купила тетради в клетку и линейку по одинако-вой цене. Всего – 10 штук. За тетради в клетку она уплатила150 тенге, а за тетради в линейку — 100 тенге. Сколько былокуплено тетрадей в клетку и линейку по отдельности?6) Запиши один возможный вариант, какими купюрамиона могла внести деньги в кассу.​

Answer 1

Ответ:

Ответ №1

Ответ:

1) 150+100=250

2)250:10=25 за одну тетрадь

3)100:25=4 в линейку

4)150:25=6 в клетку

Пошаговое объяснение:

есть другой вариант Ответ №2

1) 100+150=250 (тг)- всего потратили.

2) 250:10=25 (тг)- одна тетрадь.

3) 150:25=6 (тг)- одна тетрадь в клетку.

4) 100:25=4 (тг)- одна тетрадь в линию.

Answer 2

Problem 10: Purchasing notebooks

The problem states that a student bought notebooks with grids and notebooks with lines at the same price. The total number of notebooks purchased was 10. The student paid 150 tenge for the grid notebooks and 100 tenge for the lined notebooks. We need to find out how many notebooks of each type were purchased.

To solve this problem, let's assume that the student bought x notebooks with grids and y notebooks with lines. Since the price of both types of notebooks is the same, we can set up the following equations:

1. The total number of notebooks purchased is 10: - x + y = 10

2. The cost of the grid notebooks is 150 tenge: - x * price_per_grid_notebook = 150

3. The cost of the lined notebooks is 100 tenge: - y * price_per_lined_notebook = 100

We can solve this system of equations to find the values of x and y.

Let's solve the equations step by step:

From equation 1, we have: x + y = 10

From equation 2, we have: x * price_per_grid_notebook = 150

From equation 3, we have: y * price_per_lined_notebook = 100

Since the price of both types of notebooks is the same, we can assume that the price_per_grid_notebook is equal to the price_per_lined_notebook.

Now, let's substitute the values into the equations:

x + y = 10 x * price_per_grid_notebook = 150 y * price_per_lined_notebook = 100

Since the price of both types of notebooks is the same, we can assume that the price_per_grid_notebook is equal to the price_per_lined_notebook, so we can rewrite equation 2 and equation 3 as:

x * price_per_notebook = 150 y * price_per_notebook = 100

Now, let's solve the equations:

x + y = 10 x * price_per_notebook = 150 y * price_per_notebook = 100

From equation 1, we can solve for x: x = 10 - y

Substituting this value of x into equation 2, we have: (10 - y) * price_per_notebook = 150

Simplifying the equation, we get: 10 * price_per_notebook - y * price_per_notebook = 150

From equation 3, we can solve for y: y * price_per_notebook = 100

Now, let's substitute this value of y into equation 2: 10 * price_per_notebook - 100 = 150

Simplifying the equation, we get: 10 * price_per_notebook = 250

Dividing both sides by 10, we get: price_per_notebook = 25

Now, let's substitute this value of price_per_notebook into equation 2: x * 25 = 150

Dividing both sides by 25, we get: x = 6

So, the student bought 6 grid notebooks and 4 lined notebooks.

Problem 6: Possible denominations of money

The problem asks for one possible combination of banknotes that the student could have used to pay.

Since the student paid 150 tenge for the grid notebooks and 100 tenge for the lined notebooks, we can assume that the student used banknotes of 100 tenge and 50 tenge.

One possible combination of banknotes that the student could have used is: - 1 banknote of 100 tenge - 1 banknote of 50 tenge

Therefore, the student could have used a 100 tenge banknote and a 50 tenge banknote to pay for the notebooks.