Question

В одном контейнере на 18,8 кг апельсинов меньше, чем втором. В первый добавили 6,5 кг апельсинов, а из второго взяли 12,5 кг. Теперь в каком контейнере апельсинов больше и на сколько? Ответ: В _______ контейнере, на ____ кг

Answer 1

Ответ:

во втором, на 6,3

Пошаговое объяснение:

Answer 2

Problem Analysis

We are given two containers of oranges, and the weight of oranges in the first container is 18.8 kg less than the weight of oranges in the second container. We are also told that 6.5 kg of oranges are added to the first container, and 12.5 kg of oranges are taken from the second container. We need to determine which container now has more oranges and by how much.

Solution

Let's assume the weight of oranges in the first container before adding 6.5 kg is x kg. Then the weight of oranges in the second container is x + 18.8 kg.

After adding 6.5 kg to the first container, the weight of oranges becomes x + 6.5 kg. And after taking 12.5 kg from the second container, the weight of oranges becomes (x + 18.8 kg) - 12.5 kg.

To find which container now has more oranges, we need to compare the weights of oranges in the first and second containers after the changes.

Let's calculate the weights:

Weight of oranges in the first container after changes = x + 6.5 kg Weight of oranges in the second container after changes = (x + 18.8 kg) - 12.5 kg

To determine which container has more oranges, we can compare these two weights.

Let's solve for x:

Weight of oranges in the first container after changes = Weight of oranges in the second container after changes

x + 6.5 kg = (x + 18.8 kg) - 12.5 kg

Simplifying the equation:

x + 6.5 kg = x + 18.8 kg - 12.5 kg

x + 6.5 kg = x + 6.3 kg

Subtracting x from both sides:

6.5 kg = 6.3 kg

This equation is not possible, as it implies that 6.5 kg is equal to 6.3 kg, which is not true.

Therefore, there seems to be an error in the given information or calculations. Please double-check the values provided and try again.

If you have any further questions, feel free to ask.