Question

ЖППЖПЖП памагите СРОЧНО Задача 1. У садку росли яблуні й вишні — усього 32 дерева, причому яблунь було на 4 більше, ніж вишень. Скільки яблунь і скільки вишень росло в садку? Задача 2. За зміну майстер виточив утричі більше деталей, ніж учень. Скільки деталей виточив за зміну учень, якщо ця кількість на 18 менша, ніж кількість деталей, що виточив майстер? Задача 3. Дріт завдовжки 465 м розрізали на три частини, причому перша частина у 4 рази довша за третю, а друга на 114 м довша за першу знайдіть довжину кожної частини дроту.

Answer 1

Ответ: задача 1) 32-4=28(дерев)

28/2=14(вишень)

14+4=18(яблунь)

Видповидь: в садку росло 18 яблунь та 14 вишень.

задача 2) (18/2)*3=27(деталей) - виготовив майстер

27/3=9(деталей) - виготовив учень

Видповидь: за змину учень виготовив 9 деталей.

звдача 3) перша частина - 4х (м)

друга - 4х+114 (м)

третя - х (м)

все - 9х+114 (м)

465-114=351(м) - 9х

351/9=39(м) - третя частина

39*4=156(м) - перша частина

156+114=270(м) - друга частина

Видповидь: перша частина - 156м, друга частина - 270м, третя частина - 39м.

Пошаговое объяснение: поставь пж коронку.

Answer 2

Problem 1:

Let's solve the first problem. We are given that there are a total of 32 trees in the orchard, consisting of apple trees and cherry trees. It is also mentioned that there are 4 more apple trees than cherry trees. We need to find the number of apple trees and cherry trees in the orchard.

Let's assume the number of cherry trees in the orchard is x. Since there are 4 more apple trees than cherry trees, the number of apple trees would be x + 4.

According to the problem, the total number of trees in the orchard is 32. So, we can write the equation:

x + (x + 4) = 32

Simplifying the equation:

2x + 4 = 32

Subtracting 4 from both sides:

2x = 28

Dividing both sides by 2:

x = 14

Therefore, there are 14 cherry trees and 18 apple trees in the orchard.

Problem 2:

Now let's solve the second problem. We are given that the master produced three times more parts than the student during a shift. It is also mentioned that the number of parts produced by the student is 18 less than the number of parts produced by the master. We need to find the number of parts produced by the student.

Let's assume the number of parts produced by the student is x. According to the problem, the number of parts produced by the master would be 3x.

It is given that the number of parts produced by the student is 18 less than the number of parts produced by the master. So, we can write the equation:

3x - 18 = x

Simplifying the equation:

2x = 18

Dividing both sides by 2:

x = 9

Therefore, the student produced 9 parts during the shift.

Problem 3:

Finally, let's solve the third problem. We are given that a wire with a length of 465 m was cut into three parts. It is mentioned that the first part is 4 times longer than the third part, and the second part is 114 m longer than the first part. We need to find the length of each part of the wire.

Let's assume the length of the third part is x. According to the problem, the length of the first part would be 4x, and the length of the second part would be 4x + 114.

It is given that the total length of the wire is 465 m. So, we can write the equation:

x + (4x) + (4x + 114) = 465

Simplifying the equation:

9x + 114 = 465

Subtracting 114 from both sides:

9x = 351

Dividing both sides by 9:

x = 39

Therefore, the lengths of the three parts of the wire are 39 m, 156 m, and 153 m.

I hope this helps! Let me know if you have any further questions.