Question

Evaluate the expression (ab ² / ³ (a²b1² Whan a = -2 a=-2 and b=1

Answer 1

Ответ:

The expression is an invalid mathematical equation. In order to evaluate it, the expression would need to be corrected first. The equation should be written as follows: (a^2 * b^3) / (a^2 * b^1). With a= -2 and b = 1, the equation simplifies to -1.

Answer 2

To evaluate the expression (ab² / ³) + (a²b¹), we need to substitute the given values for a and b into the expression and perform the necessary calculations.

Given: a = -2 b = 1

Let's substitute these values into the expression:

(ab² / ³) + (a²b¹) = (-2 * 1² / ³) + ((-2)² * 1¹)

First, let's simplify the exponents:

(-2 * 1² / ³) + ((-2)² * 1¹) = (-2 * 1 / ³) + (4 * 1)

Next, let's perform the multiplication and division:

(-2 * 1 / ³) + (4 * 1) = (-2 / ³) + 4

To simplify further, we need to find a common denominator. The common denominator in this case is 3:

(-2 / ³) + 4 = (-2 / ³) + (4 * ³ / ³) = (-2 / ³) + (12 / ³)

Now that we have a common denominator, we can add the fractions:

(-2 / ³) + (12 / ³) = (-2 + 12) / ³ = 10 / ³

Therefore, the value of the expression (ab² / ³) + (a²b¹) when a = -2 and b = 1 is 10/3.