Question

Из Вершины прямого угла ABC провели лучи BD и BE так что угол ABE оказался больше угла DBE на 34 градуса, а угол CBD больше угла DBE на 23 градуса. какова градусная мера угла DBE ? СРОЧНО!!!!!!!! с пояснениями

Answer 1

34+23=57
90-57=33
90 т.к. прямой угол 

Answer 2

Given Information:

We are given that from the vertex of the right angle ABC, rays BD and BE are drawn such that angle ABE is 34 degrees larger than angle DBE, and angle CBD is 23 degrees larger than angle DBE.

Solution:

Let's assume that angle DBE is x degrees.

According to the given information, we can set up the following equations:

1. Angle ABE = Angle DBE + 34 degrees 2. Angle CBD = Angle DBE + 23 degrees

We can now solve these equations to find the value of angle DBE.

1. Angle ABE = Angle DBE + 34 degrees - Substituting the value of angle ABE, we get: - x + 34 = ABE

2. Angle CBD = Angle DBE + 23 degrees - Substituting the value of angle CBD, we get: - x + 23 = CBD

Since angle ABE and angle CBD are both greater than angle DBE, we can set up the following inequality:

3. ABE > DBE and CBD > DBE - Substituting the values of ABE and CBD, we get: - x + 34 > x and x + 23 > x

Simplifying the inequality, we get: - 34 > 0 and 23 > 0

Since both inequalities are true, we can conclude that angle DBE can take any value.

Therefore, the degree measure of angle DBE can be any real number.

Please let me know if I can help you with anything else.