Question

3 Розв'яжи задачу алгебраїчним методом. ►Микола зловив у 2 рази більше, а Тарас у 4 рази більше рибин, ніж Петро. Скільки ри- бин зловив кожний хлопчик, якщо всього вони зловили 49 рибин?​

Answer 1

Ответ:

Нехай Петро зловив х , тоді Микола - 2х , а Тарас - 4х

х+2х+4х=49

7х=49

х=49÷7

х=7 (рибин) - Петро

2х=2×7=14 (рибин) - Микола

4х=4×7=28 (рибин) - Тарас

Відповідь: Петро - 7, Микола - 14, Тарас - 28

Answer 2

To solve this problem algebraically, let's assign variables to represent the number of fish each boy caught. Let's say the number of fish caught by Petro is "x".

According to the problem, Mykola caught twice as many fish as Petro, so we can represent the number of fish caught by Mykola as "2x". Similarly, Taras caught four times as many fish as Petro, so we can represent the number of fish caught by Taras as "4x".

The total number of fish caught by all three boys is given as 49. Therefore, we can write the equation:

x + 2x + 4x = 49

Simplifying the equation, we have:

7x = 49

Dividing both sides of the equation by 7, we get:

x = 7

So Petro caught 7 fish, Mykola caught 2x7 = 14 fish, and Taras caught 4x7 = 28 fish.

Therefore, Petro caught 7 fish, Mykola caught 14 fish, and Taras caught 28 fish.