Question

Щохвилини в першу діжку з крана наливалося 3 л води, а в другу з іншого крана 2 л. 0 12 год у першій діжці було 21 л води, а в другій - 54 л. З'ясуйте, о котрій годині в першій діжці було в 4 рази менше води, ніж у другій. ​

Answer 1

Відповідь:

Покрокове пояснення:

В першу діжку за 1 хвилину наливається 3 л води, отже за t хвилин наливається 3t л води.

В другу діжку за 1 хвилину наливається 2 л води, отже за t хвилин наливається 2t л води.

Так як о 12 год у першій діжці було 21 л води, а в другій - 54 л, то ми можемо скласти систему рівнянь:

3t * x = 21

2t * x = 54

де x - час в хвилинах, за який вода нальотилася в діжки

Розв'язавши цю систему рівнянь, ми отримуємо, що x = 7 та t = 1.5.

Отже, через 7 хвилин після 12:00 в першій діжці було 3 * 7 = 21 л води, а в другій діжці було 2 * 7 = 14 л води.

Тим самим, о 12:07 год в першій діжці було в 4 рази менше води, ніж у другій.

Answer 2

Calculation of Water Flow:

To determine the time at which the first container had four times less water than the second container, we need to calculate the rate at which water is being poured into each container.

In the first minute, 3 liters of water were poured into the first container, and in the second minute, 2 liters of water were poured into the second container.

Calculation of Water Levels:

At 12:00 PM, the first container had 21 liters of water, and the second container had 54 liters of water.

To find the time when the first container had four times less water than the second container, we can set up the following equation:

21 - x = 4(54 - x)

Where x represents the amount of water poured into the first container.

Solving the Equation:

Let's solve the equation to find the value of x, which will give us the time when the first container had four times less water than the second container.

21 - x = 4(54 - x)

Expanding the equation:

21 - x = 216 - 4x

Combining like terms:

3x = 195

Dividing both sides by 3:

x = 65

Therefore, the first container had 65 liters of water poured into it.

Calculation of Time:

Since 3 liters of water are poured into the first container every minute, we can calculate the time it took to pour 65 liters of water:

65 liters / 3 liters per minute = 21.67 minutes

Therefore, it took approximately 21.67 minutes for the first container to have four times less water than the second container.

Conclusion:

At approximately 12:21 PM, the first container had four times less water than the second container.

Please note that the calculations provided are based on the information given in the question.