Question

В двух мешках всего 140 кг муки. После того, как переложили 1/8 часть муки из первого мешка во второй, кол-во муки стало поровну. Сколько кг было в каждом мешке первоначально?

Answer 1

у- 1-й мешок, х - 2-й мешок.

х+у=140;

х+1/8у=у-1/8у;

х=у-1/8у-1/8у;

х=6/8у;

6/8у+у=140;

14/8у=140;

1,75у=140;

у=80

х=140-80;

х=60

Ответ: в первом мешке было 80 кг., во втором 60 кг.

Answer 2

Problem Analysis

We are given that there are two bags of flour with a total weight of 140 kg. After transferring 1/8 of the flour from the first bag to the second bag, the amount of flour in each bag becomes equal. We need to find the initial weight of flour in each bag.

Solution

Let's assume the initial weight of flour in the first bag is x kg. Therefore, the initial weight of flour in the second bag would be (140 - x) kg.

According to the given condition, after transferring 1/8 of the flour from the first bag to the second bag, the amount of flour in each bag becomes equal. This means that the weight of flour in each bag is now (140/2) = 70 kg.

We can set up the following equation to solve for x:

x - (1/8)x = 70

Simplifying the equation:

(7/8)x = 70

Multiplying both sides by 8/7:

x = (70 * 8) / 7

x = 80

Therefore, the initial weight of flour in the first bag was 80 kg, and the initial weight of flour in the second bag was (140 - 80) = 60 kg.

Answer

The initial weight of flour in each bag was 80 kg and 60 kg, respectively.