Question

В восьми аквариумах было поровну рыбок. Установили еще один аквариум, и рыбок расселили так, чтобы во всех аквариумах, кроме одного, их стало поровну, а в одном-на 1 больше, чем в каждом из остальных. Сколько всего было рыбок, если их было меньше 100?

Answer 1

Ответ

Пошаговое объяснение:

сначала в каждом аквариуме сидело поровну по 7 рыбок.

когда поставили еще 3 аквариума, то аквариумов стало 11, значит в них стало сидеть по 5 рыбок в 10 аквариумах и 6 в 11-ом аквариуме.

ответ: 56 рыбок

Answer 2

Problem Analysis

We are given that there were an equal number of fish in eight aquariums. Then, an additional aquarium was added, and the fish were redistributed so that all the aquariums, except one, had an equal number of fish. The remaining aquarium had one more fish than each of the other aquariums. We need to determine the total number of fish, given that there were fewer than 100 fish in total.

Solution

Let's assume that there were x fish in each of the eight original aquariums. After adding the ninth aquarium, there would be x+1 fish in that aquarium. Since the fish were redistributed so that all the aquariums, except one, had an equal number of fish, there would be x fish in each of the other eight aquariums.

To find the total number of fish, we can calculate the sum of the fish in each aquarium. There are eight aquariums with x fish and one aquarium with x+1 fish. Therefore, the total number of fish is:

Total number of fish = (8 * x) + (x + 1)

We know that the total number of fish is less than 100. So, we can set up the following inequality:

(8 * x) + (x + 1) < 100

Now, let's solve this inequality to find the maximum value of x.

(8 * x) + (x + 1) < 100

Simplifying the inequality:

9x + 1 < 100

Subtracting 1 from both sides:

9x < 99

Dividing both sides by 9:

x < 11

Since x represents the number of fish in each of the eight original aquariums, it must be an integer. Therefore, the maximum value of x is 10.

Now, let's calculate the total number of fish using x = 10:

Total number of fish = (8 * 10) + (10 + 1) = 80 + 11 = 91

Therefore, if there were fewer than 100 fish in total, the total number of fish would be 91.

Answer

If there were fewer than 100 fish in total, the total number of fish would be 91.