Question

в первом букете было в 3 раза меньше роз, чем во втором . когда к первому букету добавили 8 роз а ко второму 2 розы то в обоих букетах роз стало поровну сколько роз было в первом букете первоначально​

Answer 1

Ответ:

3

Пошаговое объяснение:

Возьмем 1 букет за х, тогда

х+8=3х+2

2х=6

х=3

Answer 2

Problem Analysis

We are given two bouquets of roses, and it is stated that the first bouquet has three times fewer roses than the second bouquet. Additionally, we are told that when 8 roses are added to the first bouquet and 2 roses are added to the second bouquet, the number of roses becomes equal in both bouquets. We need to determine the initial number of roses in the first bouquet.

Solution

Let's assume that the initial number of roses in the first bouquet is x. According to the problem statement, the second bouquet has three times more roses than the first bouquet, so the initial number of roses in the second bouquet is 3x.

When 8 roses are added to the first bouquet, the total number of roses becomes x + 8. Similarly, when 2 roses are added to the second bouquet, the total number of roses becomes 3x + 2.

According to the problem, the number of roses becomes equal in both bouquets after adding the additional roses. Therefore, we can set up the following equation:

x + 8 = 3x + 2

To solve this equation, we can subtract x from both sides:

8 = 2x + 2

Next, we can subtract 2 from both sides:

6 = 2x

Finally, we can divide both sides by 2:

x = 3

Therefore, the initial number of roses in the first bouquet was 3.

Answer

The initial number of roses in the first bouquet was 3.