Question

2 целых 7/56-1 целых 9/28=? помогите пожалуйстаааааа​

Answer 1

Пошаговое объяснение:

$2 \frac{7}{56} - 1 \frac{9}{28} = \frac{119}{56} - \frac{37}{28} = \frac{45}{56}$

Answer 2

Ответ:

45\56

Пошаговое объяснение:

Приводим дроби к общему знаменателю:

2 7/56 - 1 18/56=

1 63/56- 1 18/56= 45/56-дробы несократимая

Answer 3

To solve the given expression, we need to perform the operations in the correct order. Let's break it down step by step:

1. Convert the mixed numbers to improper fractions: - 2 whole and 7/56 can be written as (2 * 56 + 7) / 56 = 119/56 - 1 whole and 9/28 can be written as (1 * 28 + 9) / 28 = 37/28

2. Subtract the fractions: - To subtract fractions, we need a common denominator. In this case, the common denominator is 56 * 28 = 1568. - Multiply the numerator and denominator of the first fraction (119/56) by 28 to get the common denominator: (119 * 28) / (56 * 28) = 3312/1568 - Multiply the numerator and denominator of the second fraction (37/28) by 56 to get the common denominator: (37 * 56) / (28 * 56) = 2072/1568

- Now, we can subtract the fractions: 3312/1568 - 2072/1568 = (3312 - 2072) / 1568 = 1240/1568

3. Simplify the fraction: - To simplify the fraction, we can divide both the numerator and denominator by their greatest common divisor (GCD). - The GCD of 1240 and 1568 is 8. - Divide both the numerator and denominator by 8: 1240/8 / 1568/8 = 155/196

Therefore, 2 whole and 7/56 - 1 whole and 9/28 = 155/196.

I hope this helps! Let me know if you have any further questions.