Question

Площадь квадрата 1444кв.м.Найти периметр прямоугольника,если известно ,что его длина в два раза меньше стороны квадрата ,а площадь прямоугольника равна площади квадрата?

Answer 1

Сторона квадрата а=√1444=38 м
длина прямоуг. 38/2=19 м
ширина прям. 1444/19=76
Периметр (19+76)*2=190 м

Answer 2

Sqrt1444=38
l=38/2=19
Spryam=1444=>
shir=1444/19*x
x=76
p=76+19=95

Answer 3

Problem Analysis

We are given the area of a square, which is 1444 square meters. We need to find the perimeter of a rectangle, where the length is two times smaller than the side of the square, and the area of the rectangle is equal to the area of the square.

Solution

Let's start by finding the side length of the square. We know that the area of a square is given by the formula: area = side length * side length. Therefore, we can solve for the side length by taking the square root of the area.

The side length of the square is √1444 = 38 meters.

Next, we need to find the length and width of the rectangle. We are given that the length is two times smaller than the side of the square. Therefore, the length of the rectangle is 38/2 = 19 meters.

To find the width of the rectangle, we can use the formula for the area of a rectangle: area = length * width. Since the area of the rectangle is equal to the area of the square, which is 1444 square meters, we can solve for the width.

1444 = 19 * width

Solving for width, we get width = 1444/19 = 76 meters.

Now that we have the length and width of the rectangle, we can calculate its perimeter using the formula: perimeter = 2 * (length + width).

Substituting the values, we get perimeter = 2 * (19 + 76) = 2 * 95 = 190 meters.

Therefore, the perimeter of the rectangle is 190 meters.

Answer

The perimeter of the rectangle is 190 meters.