Question

Сторона АС трикутника АВС у три рази більша за сторону АВ і на 3 см менша , ніж сторона ВС. Знайди сторони трикутника , якщо його периметр дорівнює 31 см .​

Answer 1

Ответ:

Сторона АС-3Х

Сторона АВ-Х

Сторона ВС-3Х+3

3Х+Х+3Х+3=31

7Х=31-3

7Х=28

Х=28:7

Х=4

Сторона АВ=4 см

Сторона АС=4•3=12 см

Сторона ВС=12+3=15 см

Проверка

4+12+15=31 см

Пошаговое объяснение:

Answer 2

Problem Analysis

We are given that the side AC of triangle ABC is three times larger than side AB and three centimeters smaller than side BC. We need to find the lengths of the sides of the triangle if its perimeter is 31 cm.

Solution

Let's assume that the length of side AB is x cm.

According to the given information, side AC is three times larger than side AB, so its length is 3x cm.

Also, side BC is three centimeters longer than side AC, so its length is 3x + 3 cm.

The perimeter of a triangle is the sum of the lengths of its sides. Therefore, we can write the equation:

x + 3x + 3 + 3x = 31

Simplifying the equation:

7x + 3 = 31

Subtracting 3 from both sides:

7x = 28

Dividing both sides by 7:

x = 4

Now that we have the length of side AB, we can find the lengths of the other sides:

- Side AC = 3x = 3 * 4 = 12 cm - Side BC = 3x + 3 = 3 * 4 + 3 = 15 cm

Therefore, the lengths of the sides of the triangle ABC are: - Side AB = 4 cm - Side AC = 12 cm - Side BC = 15 cm

Answer

The lengths of the sides of triangle ABC are: - Side AB = 4 cm - Side AC = 12 cm - Side BC = 15 cm