Вопрос задан 26.07.2018 в 07:00. Предмет Математика. Спрашивает Мукомолов Тимофей.

После разгрузки в порту осадка судна уменьшилась на 20 см.Какова масса снятого с судна груза,если

площадь сечения корпуса судна на уровне воды 2500 м2 (в квадрате)?
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Отвечает Горин Геннадий.
Дано:              Си:                  Решение:
h=20 см           0,02м        m=pV      m=1000кг/м^3*0,02м*2500м^2= 500 т
S=2500 м^2                      V=Sh
р(ро)= 1000кг/м^3            m=pSh
       
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculation of the Mass of the Removed Cargo

To calculate the mass of the removed cargo from the ship, we need to use the given information about the decrease in the ship's draft (or depth) after unloading in the port.

The decrease in the ship's draft is given as 20 cm. We also know the cross-sectional area of the ship's hull at the water level, which is 2500 m².

To calculate the mass of the removed cargo, we can use Archimedes' principle, which states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

In this case, the weight of the fluid displaced is equal to the weight of the cargo that was removed from the ship.

To calculate the mass of the removed cargo, we can use the following formula:

Mass of removed cargo = Density of water × Volume of water displaced

The volume of water displaced can be calculated using the decrease in the ship's draft and the cross-sectional area of the ship's hull at the water level.

Let's calculate the mass of the removed cargo:

1. Convert the decrease in draft from centimeters to meters: - 20 cm = 0.2 m

2. Calculate the volume of water displaced: - Volume of water displaced = Decrease in draft × Cross-sectional area of the ship's hull at the water level - Volume of water displaced = 0.2 m × 2500 m²

3. Calculate the mass of the removed cargo: - Mass of removed cargo = Density of water × Volume of water displaced

Unfortunately, I couldn't find the density of water in the search results provided. The density of water is approximately 1000 kg/m³.

Using the density of water as 1000 kg/m³, we can calculate the mass of the removed cargo. However, please note that the actual density of water may vary slightly depending on factors such as temperature and salinity.

Please note that the density of water is an approximation and may vary slightly depending on various factors.

Let's calculate the mass of the removed cargo using the density of water as 1000 kg/m³:

Mass of removed cargo = 1000 kg/m³ × (0.2 m × 2500 m²)

Mass of removed cargo = 1000 kg/m³ × 500 m³

Mass of removed cargo = 500,000 kg

Therefore, the mass of the removed cargo is 500,000 kg.

Please note that the calculated mass of the removed cargo is based on the assumption that the density of water is 1000 kg/m³.

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