
Два велосипедиста выехали одновременно из ворот дома и поехали в противоположных направлениях через
5 минут расстояние между ними было 2500 метров с какой скоростью ехал второй велосипедист если первый ехал со скоростью 200 метров в минуту решение двумя способами

Ответы на вопрос

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1) 2500 : 5 = 500 м/мин. - скорость удаления
2) 500 - 200 = 300 м/мин. - скорость второго - ответ.
Выражением : 2500 : 5 - 200
2 способ
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1) 200 * 5 = 1000 м - проехал первый за 5 мин.
2) 2500 - 1000 = 1500 м - проехал второй
3) 1500 : 5 = 300 м/мин. - скорость второго - ответ.
Выражением : (2500 - (200 * 5)) : 5



Problem Statement
Два велосипедиста выехали одновременно из ворот дома и поехали в противоположных направлениях. Через 5 минут расстояние между ними было 2500 метров. С какой скоростью ехал второй велосипедист, если первый ехал со скоростью 200 метров в минуту?Solution 1: Using Relative Speed
Let's solve this problem using the concept of relative speed.When two objects are moving in opposite directions, the relative speed between them is the sum of their individual speeds. In this case, the relative speed between the two cyclists is the sum of their speeds.
Let's assume the speed of the second cyclist is x meters per minute.
The speed of the first cyclist is given as 200 meters per minute.
After 5 minutes, the distance between them is 2500 meters.
Using the formula: Distance = Speed * Time, we can calculate the distance covered by each cyclist.
For the first cyclist: Distance1 = Speed1 * Time = 200 * 5 = 1000 meters
For the second cyclist: Distance2 = Speed2 * Time = x * 5
The total distance covered by both cyclists is the sum of their individual distances: Distance1 + Distance2 = 2500 meters
Substituting the values, we get: 1000 + 5x = 2500
Simplifying the equation: 5x = 1500 x = 1500 / 5 x = 300
Therefore, the second cyclist was traveling at a speed of 300 meters per minute.
Solution 2: Using Relative Distance
Alternatively, we can solve this problem using the concept of relative distance.Let's assume the speed of the second cyclist is x meters per minute.
The speed of the first cyclist is given as 200 meters per minute.
After 5 minutes, the distance between them is 2500 meters.
The distance covered by the first cyclist is the product of their speed and time: Distance1 = Speed1 * Time = 200 * 5 = 1000 meters
The distance covered by the second cyclist is the product of their speed and time: Distance2 = Speed2 * Time = x * 5 meters
The total distance covered by both cyclists is the sum of their individual distances: Distance1 + Distance2 = 2500 meters
Substituting the values, we get: 1000 + 5x = 2500
Simplifying the equation: 5x = 1500 x = 1500 / 5 x = 300
Therefore, the second cyclist was traveling at a speed of 300 meters per minute.
Both solutions yield the same result, confirming that the second cyclist was traveling at a speed of 300 meters per minute.
Please let me know if you need any further assistance!


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