Question

(1600+t):80=60 2000:f-670=1330 1300-(d-678)=400

Answer 1

(1600+t)÷80=60
1600+t=60×80=4800
t=4800-1600=3200

2000÷f-670=1330
2000÷f=1330+670=2000
f=2000÷2000=1

1300-(d-678)=400
d-678=1300-400=1100
d=1100+678=1778

Answer 2

To solve these equations, we'll isolate the variables one by one. Let's work on each equation separately:

1. (1600 + t) / 80 = 60

First, multiply both sides of the equation by 80 to get rid of the fraction:

1600 + t = 60 * 80 1600 + t = 4800

Now, subtract 1600 from both sides to isolate t:

t = 4800 - 1600 t = 3200

So, the solution for this equation is t = 3200.

2. 2000 / (f - 670) = 1330

First, divide both sides of the equation by 1330 to isolate the fraction:

2000 / 1330 = f - 670

Now, add 670 to both sides to isolate f:

f = (2000 / 1330) + 670

You can calculate the value of f by performing the arithmetic:

f ≈ 1.5038 + 670 ≈ 671.5038

So, the solution for this equation is approximately f ≈ 671.5038.

3. 1300 - (d - 678) = 400

First, simplify the equation by removing the parentheses:

1300 - d + 678 = 400

Now, combine like terms on the left side:

1978 - d = 400

Subtract 1978 from both sides to isolate d:

-d = 400 - 1978 -d = -1578

Finally, multiply both sides by -1 to find d:

d = 1578

So, the solution for this equation is d = 1578.